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X^3 - 3x^2 + 5x - 15 = 0 what real value of x is a solution to the above equation?
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The circumference of a circle is 5 pi cm. what is the area of the circle?
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The center on a target has a diameter of 5 inches. the whole target has a diameter of 25 inches. complete the explanation for what part of the whole target is the center. the center of the target takes up % of the whole target.
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X^3 - 3x^2 + 5x - 15 = 0 what real value of x is a solution to the above equation?...
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