Isaac has 21 green marbles and 7 blue marbles. he wants to place them in identical groups without any marbles left over. what is the greatest number of groups isaac can make? answer with !

7 groups.

Step-by-step explanation:

We have been given that Isaac has 21 green marbles and 7 blue marbles. He wants to place them in identical groups without any marbles left over.

To find the greatest number of groups Issac can make we will find the GCF of 7 and 21.

Factors of 7 are: 1, 7.

Factors of 21 are: 1, 7, 3, 21.

We can see that 7 is the greatest common factor of 7 and 21, therefore, Issac can make 7 groups from 21 green marbles and 7 blue marbles.

Let us find number of each type of marble is each group.

Therefore, there will be 3 green marbles in each group.

Therefore, there will be 1 blue marble in each group.

the system of inequity is

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

the solid line passing through the points (0,4) and (4,0).

the related equation of solid line is .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

the related equation of dashed line is

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be . the required inequality is

similarly, check the second related equation.

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is