Arectangle prism has dimensions of 1/2, 2 and 7/2 inches. how many cubes with side edges of 1 inch will fit into the prism?

Dimensions of the rectangular prism: a=1/2 inches, b=2 inches, c=7/2 inchesVolumen of the rectangular prism: Vr=abcVr=(1/2 inches)(2 inches)(7/2 inches)Vr=[ (1*2*7) / (2*2) ] inches^3Vr=14/4 inches^3Vr=7/2 inches^3
Side of the cube: s=1 incheVolume of the cube: Vc=s^3Vc=(1 inche)^3Vc=1 inche^3

Number of cubes will fit into the rectangular prism: nn=Vr/Vcn=(7/2 inches^3) / (1 inche^3)n=7/2n=3.5
3.5 cubes with side lengths of 1 inche will fit into the prism
Read more on - link

The volume of a rectangular prism is the product of its three dimensions.
 We have then:
 V = (1/2) * (2) * (7/2)
 V = 3.5 in ^ 3
 On the other hand the volume of a cube is:
 V = L ^ 3
 Where
 L = length of its sides.
 V = (1) ^ 3
 V = 1 in ^ 3
 The number of cubes inside the prism is:
 N = (3.5) / (1)
 N = 3.5
 That is, only 3 cubes of volume 1 in ^ 3 fit inside the prism.
 
 3 cubes of volume 1 in ^ 3 inside the prism.