Find a model for simple harmonic motion if the position at t=0 is 5 centimeters, the amplitude is 5 centimeters, and the period is 4 seconds. a) d=5cos(4t) b) d=5sin(pi/2t) c) d=4sin(5t) d) d=5cos(pi/2t)

Step-by-step explanation:

As at t=0 the amplitude is 5 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at x=0 is 0.

We know that, in the function

As in this case the amplitude is given to be 5, hence

Also the period is given as 4, so

As nothing is given about the horizontal and vertical shift, so putting , the function becomes,

or

As in x axis time is taken as t and in y axis distance is taken as d, so the function becomes,

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you