Ine segment xy has endpoints x(–10, –1) and y(5, 15). to find the y-coordinate of the point that divides the directed line segment in a 5: 3 ratio, the formula y = (y2 – y1) + y1 was used to find that y = (15 – (–1)) + (–1). therefore, the y-coordinate of the point that divides xy into a 5: 3 ratio is

-coordinate of the point that divides the directed line segment in a 5:3 ratio is 9.

Step-by-step explanation:

Given : Line segment XY has endpoints X(–10, –1) and Y(5, 15) and divides the directed line segment in a 5:3 ratio.

To find :  y-coordinate of the point that divides the directed line segment in a 5:3 ratio.

Solution : We have a line segment XY with ends points X(–10, –1)  and Y(5, 15).

and divided by 5: 3 ratio.

, ,

, .

By section formula :  Let P divide  line XY   in ration m : n , coordinates of P (x,y)

P =( , ).

y- coordinate = .

Plugging values , m= 5 , n = 3

y- coordinate = .

y- coordinate = .

y- coordinate = 9.

Therefore ,  y-coordinate of the point that divides the directed line segment in a 5:3 ratio is 9.

ok

step-by-step explanation:

answer for #1 is c

answer for #2 is d

can i get brainliest