What are the values of a and b in the equation a[3x-8]=b-18x

A(3x-8)=0

a=0 and x=8/3

This second line is not necessarily true. We could have a=0 OR x=8/3. They don't both have to be 0. a(3x-8)=b-18x

No solutions found

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

a*(3*x-8)-(b-18*x)=0

Step by step solution :

Step 1 :

Equation at the end of step 1 :

a • (3x - 8) - (b - 18x) = 0
Step 2 :

Equation at the end of step 2 :

3ax - 8a + 18x - b = 0
Step 3 :

Solving a Single Variable Equation :

3.1 Solve 3ax-8a+18x-b = 0

Area of circle = pi * radius^2radius is given to be 1/2 inchespi * (1/2)^2 = pi/4 inches^2 = 0.785 inches^2