If 7(t-4)-2t=4(t-3), what is the value of t?

7(t-4)-2t=4(t-3)
multiply 7 and 4 by all in parentheses
(7*t) + (7*-4) - 2t= (4*t) + (4*-3)
7t -28 - 2t= 4t - 12
combine like factors
5t - 28= 4t - 12
add 28 to both sides
5t= 4t + 16
subtract 4t from both sides
t= 16

CHECK:
7(t-4)-2t=4(t-3)
7(16-4) - 2(16)= 4(16-3)
7(12) - 32= 4(13)
84 - 32= 52
52= 52

ANSWER: t= 16

Hope this helps! :)

7 (t-4)-2t= 4 (t-3)= t = 16

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

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