Martin has 10 loose identical red socks and 10 loose identical blue socks. what is the least number of socks he would have to choose to be sure he finds a matching pair? answer only if you know the answer. lame answers will be reported.

Well, you have 2 different colors of socks, and using some simple logic we should find the answer.

 1st Case - You would draw 2 socks without them being matching, and upon the third, you are guaranteed a matching sock

2nd Case - You draw 2 socks and they end up matching

Answer x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​

step-by-step explanation: