Af(x)=2x2+4x-16
b f(x) =3x2-5x+16
c f(x) =5x2-2x-16
d f(x) =-4x2+3x+16

The graph's y-intercept is -16, so only A and C are viable answers. The axis of symmetry is x=-1, so only selection A is appropriate.


The axis of symmetry of ax^2 +bx +c is x=-b/(2a). For selection A, that is -4/(2*2) = -1. For selection C, that is -(-2)/(2*5) = 1/5, wrong in sign and in magnitude.

I'll say voice is the strongest because it give you your personal opinion on things,and your voicing your reasoning..hope that ,if not let me know what i can do :