Agame at a carnival allows you to pick on ball from a bucket of 10 identical balls. three of the balls are marked to win a prize. one game allows you two chances. if you do not pick a winning ball the first time, you put the ball back and then pick again. what is the probability that you do not pick a winning ball either pick?

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2