Will mark brainiest sara deposits $10 in an account that earns an interest rate of 5% compounded annually. what is the balance in the account at the end of 50 years? a) $114.67 b) $234.57 c) $635.21 d) $75.26 8) davis puts $5,000 each year in an account that earns 5% annual interest, compounded annually. his brother mike puts $5,000 each year in a safe in his bedroom. after the first 10 years of doing this, how much more money does davis have than mike? round your answer to the nearest dollar. a) $20,524 b) $2,500 c) $31,445 d) $8,144

 1) Option A is the correct answer

 2) No options are correct.

Explanation:

The balance after n years is given by, B = P (1+r)ⁿ, where P is the principal, r is the rate of interest and n is the number of years.

  1)                 B = 10 (1+0.05)⁵⁰= 114.67$

      Option A is the correct answer.

  2) Balance of Davis after 10 years,  B = 5000 (1+0.05)¹⁰=8144.47 $

       How much more money does Davis have than Mike = 8144.47-5000= 3144.47$ = 3144$

    No options are correct.      

1 A) $114.67

2 A) $20,524

Explanation: The balance after n years is given by, B = P (1+r)ⁿ, where P is the principal, r is the rate of interest and n is the number of years...

1)                 B = 10 (1+0.05)⁵⁰= 114.67$

2)Step-by-step explanation:

Davis: each year he adds $5,000 and he earns 5%.

1: 5,000(1.05) = 8,144.47

2: 13,144.47(1.05) = 13,801.69

3: 18,801.69(1.05) = 19,741.78

4: 24,741.78(1.05) = 25,978.87

5: 30,978.87(1.05) = 32,527.81

6: 37,527.81(1.05) = 39,404.20

7: 44,404.20(1.05) = 46,624.41

8: 51,624.41(1.05) = 54,205.63

9: 59,205.63(1.05) = 62,165.91

10: 67,165.91(1.05) = 70,524.21

Mike: he saves $5,000 each year, no interest.

$5,000 · 10 = $50,000

$70,524.21 − $50,000 = $20,524

reduce the friction between its moving parts

step-by-step explanation:

in fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.