The quadratic function f has a vertex at (3,4) and opens upward. the quadratic function g is shown below. which statement is true? g(x)=2(x-4)^2+3asap

The minimum value of f is greater than the minimum value of g.

Step-by-step explanation:

The vertex of a parabola is an extreme point of the function.

If a parabola opens upward, then vertex represent its maximum point and if a parabola opens downward, then vertex represent its minimum point.

The vertex of quadratic function f has a vertex at (3,4) and opens upward. It means the minimum value of f is 4 at x=3.

The given function is

           .... (1)

The vertex form of a parabola is

           .....(2)

Where, (h,k) is vertex and a is a constant.

On comparing (1) and (2) we get

Since a=2>1, therefore it is an upward parabola and its vertex is minimum point of the function.

The minimum value of g is 3 at x=4.

Therefore the minimum value of f is greater than the minimum value of g.

cant open file sorry!

step-by-step explanation:

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column