What is the equation of the line that is parallel to the line y = 1/3x + 4 and passes through the point (6, 5)? y = -1/3x + 3 y= -1/3x + 7 y= 3x - 13 y= 3x + 5

Find Slope

y = -1/3 x + 4                                      
Slope = -1/3                                       
Slope of the parallel line = -1/3          


Insert slope into y = mx + c

y = -1/3 x + c                                  


Find y-intercept

y = -1/3 x + c                                   
at point (6, 5)
5 = -1/3 (6) + c                                 
5 = - 2 + c                                         
c = 5 + 2                                         
c = 7


Insert y-intercept into y = -1/3x + c

y = -1/3 x + 7 


y = -1/3 x + 7 (Answer B)
 

3x+9+4x+x=8x+9that's the answer for your question.