In δjkl, solve for x. (4 points) triangle jkl where angle k is a right angle. kl measures 34. jl measures x. angle j measures 27 degrees.

X= 75.kl is the side opposite  ∠j, and x is the hypotenuse of the triangle.  we can use these two sides for the sine ratio: sin j = opposite/hypotenusesin 27 = 34/xmultiply both sides by x to remove it from the denominator: xsin 27 = 34divide both sides by sin 27: xsin 27/sin 27 = 34/sin 27x = 74.89 = 74.5