Alake near the arctic circle is covered by a thick sheet of ice during the cold winter months. when spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a rate of 0.20.20, point, 2 meters per week. after 777 weeks, the sheet is only 2.42.42, point, 4 meters thick. let s(t)s(t)s, left parenthesis, t, right parenthesis denote the ice sheet's thickness sss (measured in meters) as a function of time ttt (measured in weeks).

Iadded a screenshot with the proper wording of the question.answer: s(t) = -0.2t + 3.82explanation: the equation that represents the given scenario is: s(t) = rate * t + xwhere: x is the initial value of the thicknessrate is given as -0.2 m/week where the negative sign represents a decrease in the thicknessthe equation now becomes: s(t) = -0.2t + xnow, we need to get the value of the x.we are given that after 7 weeks, the thickness of the sheet became 2.42 m.this means that: at t = 7: s(7) = 2.42therefore, we can get x as follows: s(7) = -0.2(7) + x = 2.42-1.4 + x = 2.42x = 2.42 + 1.4x = 3.82the final equation is: s(t) = -0.2t + 3.82hope this : )

Hope this ; )