Atrapezoidal mural with bases 11m and 9m and height 6m needs to be painted. what is the cost of painting it if a box of paint in any color is $16 and with each box can be painted area of 12m2.

The total cost to paint the mural will be $80.

First, we need to find the area of the trapezoid. The formula is one-half times the height times the sum of the bases.

0.5 x 6 (9 + 11) = 60 m^2

Each can will cover 12 m^2, so divide 60 by 12 to find that we need 5 cans.

The cost of each can is $16, so 5 x 16 = $60.

Ithink it's the first one ( let me know if it right)