Amanager wishes to build a 3-sigma range chart for a process. the sample size is five, the mean of sample means is 16.01, and the average range is 5.3. from table s6.1, the appropriate value of d3 is 0, and d4 is 2.115. what are the ucl and lcl, respectively, for this range chart? a. 6.3 and 0 b. 33.9 and 0 c. 11.2 and 0 d. 33.9 and 11.2 e. 31.91 and 0.11

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

i think it would be 42cm

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

there is no answer sorry!

step-by-step explanation: