Ascientist is studying the motion of a particular glacier. he notes that this glacier has moved 2 over 3 of a meter in 3 over 4 of a day. what is the unit rate in meter(s)/day of this glacier?

The glacier has moved 2 over 3 of a meter in 3 over 4 of a day.

Distance moved by glacier = 2 over 3 = 2/3 m

Duration in which 2/3 distance was moved = 3 over 4 of a day = 3/4 day

So we have to find unit rate in meter(s)/day.

Unit rate can be found by dividing distance moved by duration in which the distance was moved.

So finding unit rate:

We are given distance moved 2/3 and duration as 3/4.

Plugging these values in the formula for unit rate,

In division of fraction, we take reciprocal of second fraction and multiply it with the first.

Unit rate = 8/9 m/day

Answer : Unit rate at which glacier is moving is (8/9) meters per day.

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4