Abox was measured with a degree of accuracy to the nearest 2cm; 24cm × 24cm × 20cm. what is the smallest possible volume of the box to the nearest cm3?

8712

Step-by-step explanation:

since the box was measured to the nearest 2 cm

we will assume  its dimensions would be ( + or - ) 2cm each

hence for the smallest possible volume of the box the dimensions would be

= (24 - 2 ) cm * ( 24 - 2 ) cm  * ( 20 - 2 ) cm

= 22 * 22 * 18 = 8712

this would be the smallest possible volume of the box to the nearest cm3

10 * 563.67 = 5636.7

(a) the volume of the cone is 20/3 in3

hence, option a is correct.