Will give ! you must explain how to ! can someone tell me how to solve this equation for a hyperbola? andxy = 12

2y² - 3x² = 6

To put the hyperbola in standard form, divide everything by 6

(2/6)y² - (3/6)x² = 6/6
Standard form:
(1/3)y² - (1/2)x² = 1

hyperbola opens up/down NOT sideways (because its y² -x²). 
then the a=√3 and b=√2
(h,k) = (0,0)

Not sure what needs to be done with xy=12

I’m not sure how this works