Aquadratic function y = f ( x ) y=f(x) is plotted on a graph and the vertex of the resulting parabola is ( − 4 , − 5 ) (−4,−5). what is the vertex of the function defined as g ( x ) = f ( − x ) + 3 g(x)=f(−x)+3?

we know that

 g(x)=f(−x)+3

  that means

point (x,y) in the graph f(x) becomes a point (-x, y+3) in the graph g(x)

 therefore

 the point (-4,-5) > becomes a point (4,-5+3) > (4,-2)

the answer is

the vertex is the point (4,-2)

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)