If x2 + y2 = 100 and dy/dt = 4, find dx/dt when y = 6. (enter your answers as a comma-separated list.) dx dt

x^2 + y^2 =100

put y = 6

x^2 + 36 = 100

x^2 = 64

x = 8

now, differentiating given equation with respect to 't'

2x.dx/dt + 2y.dy/dt  = 0

put x = 8 y = 6 and dy/dt = 4

2.8.dx/dt + 2.6.4 = 0

we get dx/dt = -3

were is the equation

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse