How many solutions does the equation |x + 6| − 4 = c have if c = 5? if c = −10? complete the explanation

Step-by-step explanation:

We know

for any real value of a.

|a| = b > 0 -  two solutions: a = b or a = -b

|a| = 0 - one solution: a = 0

|a| = b < 0 - no solution

|x + 6| - 4 = c

for c = 5:

|x + 6| - 4 = 5           add 4 to both sides

|x + 6| = 9 > 0   TWO SOLUTIONS

for c = -10

|x + 6| - 4 = -10           add 4 to both sides

|x + 6| = -6 < 0   NO SOLUTIONS

Calculate the solutions for c = 5:

|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9         subtract 6 from both sides

x = 3 or x = -15

it should be a and d. lmk if i'm wrong xd