Finish the steps below to write a quadratic function for the parabola shown. use the vertex form, f(x) = a(x – h)2 + k, and substitute in the values for h and k. f(x) = a(x – 5)2 + 3 use another point and substitute in values for x and f(x). solve for a. 5 = a(6 – 5)2 + 3 write the function, using the values for h, k, and a.

The quadratic function is f(x) = 2( x - 5 )² + 3

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :

From the value of Discriminant , we know how many solutions the equation has by condition :

D < 0 → No Real Roots

D = 0 → One Real Root

D > 0 → Two Real Roots

An axis of symmetry of quadratic equation y = ax² + bx + c is :

Let us now tackle the problem!

Given:

The stationary point (h , k) = (5 , 3)

The point ( 6 , 5 ) passes through graph , then:

The quadratic function will be :

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Quadratic , Equation , Discriminant , Real , Number

its definatley   this on your answer choice?

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17