Find an equation of a plane containing the line r=⟨−5,−1,−1⟩+t⟨−6,10,−5⟩r=⟨−5,−1,−1 ⟩+t⟨−6,10,−5⟩ which is parallel to the plane 5x+4y+2z=−265x+4y+2z=−26

where is the diagram? shown below where? ?

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92