Use the normal distribution of fish lengths for which the mean is 11 inches and the standard deviation is 5 inches. assume the variable x is normally distributed. left parenthesis a right parenthesis what percent of the fish are longer than 14 inches? left parenthesis b right parenthesis if 500 fish are randomly selected, about how many would you expect to be shorter than 9 inches?

27.43% of the fish will be longer than 14 inches.

All we need to do is find the z-score and then the percent.

(14 - 11) / 5 = 0.6 which gives a percent of 27.43% over this amount.

For the fish shorter than 9 inches:
(9 - 11) / 5 = -0.4 which gives a percent of 34.46% under this amount.

34.46% of 500 is about 172 fish.

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )