Given:
ad | | bc
ad = bc
prove:
adm bcm
which of the following reasons will complete the proof?
sas
asa
sss

- "ASA congruence postulate" is the reason which completes the proof.

Explanation:-

Given:- AD | | BC  and AD = BC

To prove:- ΔADM ≅ΔBCM

Proof:-   Statement         Reason

1.             AD=BC                 [Given]

2.  ∠1=∠3 ; ∠2=∠4   [If lines parallel, then alternate interior angles are equal]

3.             ΔADM ≅ΔBCM   [ASA congruence postulate]

Thus, "ASA congruence postulate" is the reason which completes the proof.

afjnawenkfnjaw; enkanwelwaklalejjaw; fij

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.