The manufacturer of a new compact car claims the miles per gallon (mpg) for the gasoline consumption is mound-shaped and symmetric with a mean of 24.6 mpg and a standard deviation of 11.2 mpg. if 30 such cars are tested, what is the probability the average mpg achieved by these 30 cars will be greater than 27

0.121

Step-by-step explanation:

Given : The manufacturer of a new compact car claims the miles per gallon (mpg) for the gasoline consumption is mound-shaped and symmetric i.e. a normal distribution with

Sample size : n= 30

Let x be a random variable that represents the gasoline consumption.

Z-score :

For x= 27

Now, the probability the average mpg achieved by these 30 cars will be greater than 27 will be :-

Hence, the probability the average mpg achieved by these 30 cars will be greater than 27 = 0.121

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation: