Which choice is the conjugate of the expression below when x > = 6? sqrt x-6-3a. sqrt x-6+3b. sqrt x+6+3c. sqrt x-6-3d. sqrt x+6-3

Option A)

Step-by-step explanation:

Given is an expression in x as

This will be real only for x>=6

(That is given already)

Now to find conjugate

Since x-6 is inside root sign, we can take this as one term.

Next term is -3.  To find conjugate we write the root sign term as it is and change the sign of next term from negative to positive

i.e. -3 becomes +3

Hence conjugate would be

Hence option A is right

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d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.