Mathematics, 26.07.2019 06:00 24chrim
What is the inverse of f(x)=x4+7 for x≥0 where function g is the inverse of function f? g(x)= 4√x+7, x≥−7 g(x)= 4√x−7, x≥7 g(x)=x√4−7, x≥0 g(x)=x√4+7, x≥0
Answers: 2
![x-7=y^4\\ \\ \text{now to get rid of exponent 4 from y, we take fourth root both sides.}\\ \text{so we get}\\ \\ \sqrt[4]{x-7}=y\\ \\ \text{hence the inverse function is }g(x)=\sqrt[4]{x-7}\\ \\ \text{we know that for a function its domain is the range of its inverse function}\\ \text{and the ragne of the function is domain of the inverse function.}\\ \\ \text{here observe that the range of f(x) is }f(x)\geq 7, \text{ domain of}](/tpl/images/0133/9155/7b21f.png)
![\text{inerse function g(x) would be }x\geq 7\\ \\ \text{hence the inverse of the function is}\\ \\ g(x)=\sqrt[4]{x-7}, \ \ \ x\geq 7](/tpl/images/0133/9155/322c4.png)
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What is the inverse of f(x)=x4+7 for x≥0 where function g is the inverse of function f? g(x)= 4√x+7...
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