Complete the square to transform the quadratic equation into the equation form (x – p)2 = q. x2 + 14x + 34 = 5 a) (x - 7)2 = 20 b) (x + 7)2 = 20 c) (x - 14)2 = 28 d) (x + 14)2 = 28 (its not a)

B)(x + 7)^2 = 20

You can subtract 34 from the original equation to get

... x^2 +14x = -29

Now, you can add the square of half the x-coefficient, and you will have ...

... x^2 +14x +49 = -29 +49

... (x +7)^2 = 20 . . . . . . matches selection B

Comment on answer choice A

The question asks for the form (x -p)^2 = q, but that does not mean that p must be positive. Here, p=-7 and q=20.

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12