Amir wants to show that tan3θ = (3tanθ-tan^3θ)/(1-3tan^2θ). he says he should use the double angle formula for the tangent function to do this. is he correct? a. yes he can write tan 3θ= tan 2(3/2 θ) and use the double angle formula b. yes he can write tan 3θ=(2θ+θ) and use the sum formula followed by the double angle formula c. no. because 3 is not a multiple of 2, he will have a 3/2 θ term that cannot be simplified d. no. because tan 2θ=(2tanθ)/(1-tan^2θ) there is no way to multiply the denominator by 3 to obtain 1-3tan^2θ