Geometry need asap will assign ! 11. in triangle def, md = 43 degrees, me = 62 degrees, and ef = 22 in. what is de to the nearest tenth of an inch?

Answer
31.12 in

Explanation
To get the length required, lets first find angle mF,
mF = 180 – (43 + 62) =75o
Now we can use the sin rule to find length DE.
a/sin⁡A =b/sin⁡B Where a and b are the length opposite to angle A and B respectively.
DE/sin75=22/sin⁡43
DE=(22 sin⁡75)/sin⁡43
DE=31.12 in