Which values of x are point(s) of discontinuity for this function? explain how you did it. g(x)= {-4, x< =-2} {-x^2, -2< x< 0} {x^2, 0< x< 2} {2, x> =2} answer choices (check all that apply): x=-4 x=-2 x=0 x=2 x=4hurry! will mark brainliest!  

The correct answers are:
x = 0
x = 2

Explanation:
When x < 0, the value of y = -.
When x > 0, the value of y = .
When x = 0, there is no value of y mentioned in the conditions; it means that there is discontinuity at x = 0.

When x < 2, the value of y = .
When x >= 2, the value of y = 2.

It means that, at x = 2, there is a discontinuity because the graph of y =  is not touching the graph of y = 2 at x = 2.

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