Arectangular corral is enclosed using 120 m of fencing. the corral uses the side of a barn as one of its sides, so fencing is required on three sides of the rectangular region. what dimensions would maximize the area enclosed by the fence?

Area is maximized when half the fence is used parallel to the barn and the other half is perpendicular. Dimensions of 30 m by 60 m will maximize the enclosed area.


Let x represent the fence length parallel to the barn. The area is
.. A = x(120-x)/2
This is the equation of a downward-opening parabola with vertex (maximum) at x=60, halfway between the zeros at x=0 and x=120.

Okay so for every triangle has three angles that always add up to 180 degrees. and to tell the difference between whether they are secure, right or obtuse is that acute: has one angle that is less than 90 degrees. right triangle means there is at least one angle that is exactly 90 degrees. and an obtuse angle has an angle that is bigger than 180 degrees. i’ll do #13 as an example: 13. 40 and 50 so if every triangle has 180 degrees 40+50= 90 degrees then180-90= 90 degrees so the third angle is 90 degrees and because this triangle has a 90 degree angle it means it is a right triangle

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