Which statement about the asymptotes is true with respect to the graph of this function? f(x) = 3x2 – 3 x2 – 4

There are two vertical asymptotes at x = 2 and x = -2.

It looks like you missed a division sign in your problem to create a fraction that would have asymptotes.

The denominator would factor to (x + 2)(x - 2). Since we can't have zero in the denominator, we will have an asymptote at 2 and -2. This is because those values would make the denominator zero.