Quadrilateral abcd is located at a(−2, 2), b(−2, 4), c(2, 4), and d(2, 2). the quadrilateral is then transformed using the rule (x − 2, y + 8) to form the image a'b'c'd'. what are the new coordinates of a', b', c', and d'? describe what characteristics you would find if the corresponding vertices were connected with line segments.

Given vertices of the Quadrilateral ABCD :

A(−2, 2),

B(−2, 4),

C(2, 4), and

D(2, 2).

The quadrilateral is then transformed using the rule (x − 2, y + 8).

Let us find the coordinate  A', B', C', and D' by rule (x − 2, y + 8).

A(−2, 2) ---> (-2-2 , 2+8) = (-4, 10)

B(−2, 4) ---> (-2-2, 4+8) = (-4, 12)

C(2, 4), ---> ( 2-2, 4+8) = (0, 12)

D(2, 2) ---> (2-2, 2+8) = (0, 10).

So, the coordinates of A', B', C', and D' are

A'(-4, 10), B'(-4, 12), C'(0, 12), and D'(0, 10).

For the new coordinates we get we can say that each of the coordinate A', B', C', and D' moved 2 unit left and 8 units up.

its a straight line parallel to the time axis

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17