Arocket ship is two miles above sea level when it begins to climb at a constrast angle of 3.5° for the next 40 ground miles. about how far above sea level is a rocket ship after its climb? a. 2.4 mib. 4.4 mic. 653.9 mid. 655.9 mi

b). 4.4 miles

Step-by-step explanation:

Given :

Distance of the rocket above sea level = 2 miles

Angle of climb = 3.5°

Horizontal ground distance = 40 miles

Therefore, distance traveled by the rocket ship

tan θ = opposite / adjacent

tan 3.5 = BC / AB

tan 3.5 = x / 40

x = 40 x tan 3.5

x = 2.44 miles

Therefore, distance traveled by the rocket ship above the ground level after climb = 2 + 2.44

                 = 4.44 miles

1.30

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.