50 points but i really need a break down on how to solve this, . at what point(s) do these graphs intersect? y=x^2+3x-5 y=4x+1 seth’s solution: y=x^2+3x-5 y=4x+1 x^2+3x-5=4x+1 x^2-x-6=0 (x-3) (x+2)=0 x=3 and x=-2 the graphs intersect at. (-2, 0) and (3, 0) is seth’s solution correct? explain

We have the following system of equations:
 y = x ^ 2 + 3x-5
 y = 4x + 1
 Equating the equations:
 x ^ 2 + 3x-5 = 4x + 1
 Rewriting:
 x ^ 2-x-6 = 0
 Factoring:
 (x-3) (x + 2) = 0
 Solutions:
 x = 3 and x = -2
 We evaluate the function for:
 x = 3
 y = (3) ^ 2 + 3 (3) -5 = 13
 y = 4 (3) +1 = 13
 x = -2
 y = (- 2) ^ 2 + 3 (-2) -5 = -7
 y = 4x + 1 = -7
 The solutions are:
 (-2, -7) and (3, 13)
 
 Seth's solution is NOT correct

The system of equations is not completely solved.

y=x^2+3x-5 
y=4x+1 
x^2+3x-5=4x+1 
x^2-x-6=0 
(x-3) (x+2)=0 
x₁=3 and x₂=-2 

now we solve for y:
y=4x+1 
y₁ = 4*3+1 = 13
y₂ = 4(-2) + 1 = -7

The graphs intersect at. (-2, -7) and (3, 13) 

Ithink it is15not sure tho