Suppose you are flying a kite that is 50 feet long. while flying, there is a constant gust of wind that blows the kite to an angle of 60° with the ground. how high, in feet, is the kite above the ground

Height of the kite above the ground =  43.301270189  feet

Step-by-step explanation:

The illustration above forms a right angled triangle. The right angle triangle have an hypotenuse, adjacent side and opposite sides.

The hypotenuse is given as 50 feet , the angle with the ground is 60°. Using the SOHCAHTOA principle we can find the height of the kite above the ground which is the opposite side .

sine 60°  = opposite/hypotenuse

sine 60° = opposite/50

0.8660254038 = opposite/50

cross multiply

opposite = 0.8660254038 × 50

opposite =  43.301270189  feet

Height of the kite above the ground =  43.301270189  feet

The image below is what the illustration forms(right angled triangle)

idk

step-by-step explanation:

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.