What are the points of discontinuity? are they all removable? show your work. y= (5-x)/x^2-6x+5

We have the following equation:
 y = (5-x) / x ^ 2-6x + 5
 Rewriting we have:
 y = (5-x) / (x-5) * (x-1)
 The discontinuity points are:
 x = 5
 x = 1
 x = 5 is removable. For this, we rewrite the function again:
 y = (-1 * (5-x)) / (- 1 * (x-5) * (x-1))
 y = ((x-5)) / ((x-5) * (1-x))
 We cancel similar terms:
 y = 1 / (1-x)
 
 the points of discontinuity are:
 x = 5
 x = 1
 x = 5 is removable