Six houses are located along the same road; the distances are shown. where should the school bus stop to make the sum of distances from every house to the stop as small as possible? answer i need it i don't get : ( the picture is attached.

Hey there :)

Now lets name each house

    A             B              C              D             E                  F
500ft <-> 500ft <-> 500ft <-> 500ft <-> 500ft   <->   2000ft

Let's say the bus stops at A
= 0 ( from A ) + 500 ( from B ) +  500 + 500 ( from C ) + 500 + 500 + 500 ( from D ) + 500 + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 500 + 2000 ( from F )
= 0 + 500 + 1000 + 1500 + 2000 + 4000
= 9000 ft

at B
= 500 ( from A ) + 0 ( from B ) + 500 ( from C ) + 500 + 500 ( from D ) + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 2000 ( from F )
= 500 + 0 + 500 + 1000 + 1500 + 3500
= 7000 ft

at C
= 500 ( from A ) + 500 + 500 ( from B ) + 0 ( from C ) + 500 ( from D ) + 500 + 500 ( from E ) + 500 + 500 + 2000 ( from F )
= 500 + 1000 + 0 + 500 + 1000 + 3000
= 6000 ft

Do the same for D ,  E  and F

at D
= 6000 ft

at E 
= 7000 ft

at F
= 15000 ft

You will find that the bus should stop at either C or D to make the sum of distances from every house to the stop as small as possible. 

Ttgffgfdddtdydyfydys

The correct answer is $90