Find the value of q, for which the difference between the roots in the equation x2−10x+q=0 is equal to 6.

According to the quadratic formula,

-b plus or minus √(b^2 - 4ac)

x =

2a

In this particular case (x^2 - 10x + q), a = 1, b = -10, and c = q. Thus:

-(-10) plus or minus √(100-4q) 10 plus or minus √4√(25-q)

x = =

2 2

and this reduces to:

x = 5 plus or minus √(25-q).

Assuming that 5 + √(25-q) is larger than 5 - √(25-q), we can write:

5 + √(25-q) - (5 - √(25-q)) = 6, or √(25-q) + √(25-q) = 6, or √(25-q) = 3.

Squaring both sides, we get: 25-q = 9, or

q = 16 (answer)

If q = 16, then the difference between the two roots will be +6.

answer: hi

step-by-step explanation:

answer: it's upside down and i can't read it

step-by-step explanation: