Plz ! will give ! two number cubes are rolled. what is the probability that the first lands on 6 and the second lands on an odd number? enter you answer, as a fraction in simplified form, in the box.

The probability of two independent events both occurring is the product of their individual probabilities. The probability of rolling a 6 is 1/6 because there are 6 total numbers. The probability of rolling a odd number is 1/2, because there are an equal number of odd and even numbers on a die. Now multiply those probabilities together to get 1/6 * 1/2 = 1/12. 1/12 is the chance to roll a 6 and then roll an odd number.