Given the system of equations presented here: 3x + 5y = 29 x + 4y = 16 which of the following actions creates an equivalent system such that, when combined with the other equation, one of the variables is eliminated? a) multiply the second equation by −1 to get −x − 4y = −16 b) multiply the second equation by −3 to get −3x − 12y = −48 c) multiply the first equation by −1 to get −3x − 5y = −29 d) multiply the first equation by −3 to get −9x − 15y = −87

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.