Ninety-three passengers rode in a train from city a to city b. tickets for regular coach seats cost $122. tickets for sleeper cars seats cost $284 the receipts for the trip totaled $18,960. how many passengers purchased each type of ticket? the number of coach tickets purchased was the number of sleeper car tickets purchased was

number of coach tickets = 46 tickets
number of sleeper car tickets = 47 tickets

Explanation:
Assume that number of coach tickets is x and that number of sleeper car tickets is y

We are given that:
1- Total number of tickets purchased is 93. This means that:
x + y = 93
This can be rewritten as:
x = 93 - y > equation I
2- coach ticket costs $122, sleeper car ticket costs $284 and that the total receipt was for $18960. This means that:
122x + 284y = 18960 > equation II

Substitute with I in II and solve for y as follows:
122x + 284y = 18960
122(93-y) + 284y = 18960
11346 - 122y + 284y = 18960
162y = 7614
y = 7614 / 162
y = 47

Substitute with y in equation I to get x as follows:
x = 03 - y
x = 93 - 47
x = 46 

Hope this helps :)

Im not that good with division but i think 5 is -6but dont quote me on thatim not the best in division but thats my answer