At noon, ship a is 180 km west of ship b. ship a is sailing east at 35 km/h and ship b is sailing north at 30 km/h. how fast is the distance between the ships changing at 4: 00 pm?

If we let the coordinates of each ship be (x, y) with the positive directions of these coordinates corresponding to East and North, then the positions of the ships t hours after noon are

Ship A
  (-180+35t, 0)

Ship B
  (0, 30t)

The distance between them is the "Pythagorean sum" of the difference in their coordinates:
  d = √((-180 +35t)² +(-30t)²)
    = √(32400 -12600t +2125t²)
The rate of change of this distance is
  dd/dt = (2125t -6300)/√(32400 -12600t +2125t²)

At 4 pm, the value of this rate of change is
  (2125*4 -6300)/√(32400 -12600*4 +2125*4²)
  = 2200/√16000
  ≈ 17.39 km/h

The distance between the ships is increasing at about 17.39 km/h at 4 pm.

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ωє ιт ¢αи вє ωяιттєи αѕ

тнє єχα¢т fσям: 89/9тнє ∂є¢ιмαℓ fσям: 9.ιт яєαρєαтѕ)αи∂ тнє мιχє∂ иυмвєя fσям 9 8/9

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ уσυ συт