Find the first term, a1, of an arithmetic sequence if a15 = 136 and a19 = 168. 32/23 8 24 23

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.