∠1 and ∠2 are a linear pair, and ∠2 and ∠3 are vertical angles. m∠2=(5+4y)∘ and m∠3=(6y−25)∘ . what is m∠1 ? 65° 85° 95° 115°

Vertical angles are opposite to each other and they are equal to each other.
Given that:
∠2 and ∠3 are vertical angles and m∠2=(5+4y)° and ​ m∠3=(6y−25)°
then
5+4y=6y-25
solving for y we get:
4y-6y=-25-5
-2y=-30
hence
y=15
thus
m∠2=(5+4y)
=5+4(15)
=5+60
=65
since ∠1 and ∠2 are linear angles, then:
∠1=180-∠2
∠1=180-65=115°

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