1) a right triangle has a side that measures 4 m and a hypotenuse that measures8.5 m. what is the measure of the other side of the triangle 2) you want to divide a square piece of paper into two equivalent triangles. if the square measures 20 cm on each side, what will the third side of each triangle measure

1) Use the pathagreom theorem; a^2+b^2=c^2
(The hypotenuse is always c. The other two legs can be either a or b.)
*use x for the unknown side*
1. Plug in the measurements
4^2+x^2=8.5^2
2. Solve
16+x^2=72.25
RADICAL(56.25)=> 7.5
The measure of the other side of the triangle (x) is= 7.5 m

2) Draw a square with the measure of 20 cm on each side.
Draw a diagonal line across the square.
(Use the pathagroeam theorem)
We know that the legs are 20, and 20. The hypotenuse is what we are trying to find (x).
1. Plug in the measurements
20^2+20^2=x^2
2. Solve
800= x^2
20 RADICAL(2)=> 28.28
The measure of the other side of the triangle (x) is= 28.3 cm

Dwould be the answer